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在Oracle SQL中启动和连接

发布时间:2021-03-30 21:52:33 所属栏目:百科 来源:网络整理
导读:我有桌子如下 帐户 CUSTOMER_ID PAYING_ACCOUNT_ID PARENT_ACCOUNT_ID ACCOUNT_ID COMPANY_ID 24669 24669 24669 24669 0 24671 24671 24669 24671 0 24670 24670 24669 24670 0 3385217 3385217 24670 3385217 0 158 158 158 158 0159 159 158 159 0160 1

我有桌子如下

帐户

CUSTOMER_ID   PAYING_ACCOUNT_ID   PARENT_ACCOUNT_ID     ACCOUNT_ID   COMPANY_ID 
24669         24669               24669                 24669        0 
24671         24671               24669                 24671        0  
24670         24670               24669                 24670        0 
3385217       3385217             24670                 3385217      0 
158           158                 158                   158          0
159           159                 158                   159          0
160           160                 159                   160          0
161           161                 160                   161          0 
162           162                 160                   162          0
180           180                 180                   180          0

这是DDL

CREATE TABLE "SYSTEM"."ACCOUNT"
("CUSTOMER_ID"       NUMBER(20,0) NOT NULL ENABLE,"PAYING_ACCOUNT_ID" NUMBER(20,0),"PARENT_ACCOUNT_ID" NUMBER(20,"ACCOUNT_ID"        NUMBER,"COMPANY_ID"        NUMBER)

这是我的查询

select  lpad(' ',2*level) || A.ACCOUNT_ID AS LEVEL_LABEL,LEVEL,A.* 
      from ACCOUNT A 
start with PARENT_ACCOUNT_ID IN 
                       (select PARENT_ACCOUNT_ID 
                          from ACCOUNT 
                         where ACCOUNT_ID IN 
                                        (select PARENT_ACCOUNT_ID
                                           from ACCOUNT 
                                          where parent_account_id != account_id)
                                            and ACCOUNT_ID = PARENT_ACCOUNT_ID) 
   CONNECT BY NOCYCLE  PRIOR A.ACCOUNT_ID = A.PARENT_ACCOUNT_ID;

查询的主要目的是选择具有层次关系的数据,即PARENT_ACCOUNT_ID& ACCOUNT_ID,但是我得到了查询返回的重复数据

任何建议都非常感谢.谢谢

解决方法

为什么不简单:

SELECT level,* FROM accounts
 START WITH parent_account_id = account_id
 CONNECT BY PRIOR account_id = parent_account_id
         AND account_id <> parent_account_id

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