HDU-2016 Multi-University Training Contest 3-Sqrt Bo-大数开
发布时间:2021-02-23 03:30:04 所属栏目:大数据 来源:网络整理
导读:Sqrt Bo Time Limit: 2000/1000 MS (Java/Others)????Memory Limit: 131072/131072 K (Java/Others) Total Submission(s): 0????Accepted Submission(s): 0 Problem Description Let's define the function? f(n)=?n??√? . Bo wanted to know the minimum
Sqrt BoTime Limit: 2000/1000 MS (Java/Others)????Memory Limit: 131072/131072 K (Java/Others)Total Submission(s): 0????Accepted Submission(s): 0 Problem Description Let's define the function? Bo wanted to know the minimum number? note: It is a pity that Bo can only use 1 unit of time to calculate this function each time. And Bo is impatient,he cannot stand waiting for longer than 5 units of time. So Bo wants to know if he can solve this problem in 5 units of time. ? Input This problem has multi test cases(no more than? Each test case contains a non-negative integer? Output For each test case print a integer - the answer? Sample Input 233 233333333333333333333333333333333333333333333333333333333? Sample Output 3 TAT? 题目意思:对一个数开方,能在五次之内取整得到0的就输出次数;不能或者是0的话就输出TAT。。解题思路:这题longlong暴力就能过,队友很快就过了~然而我当时没想到,只想到了大数……QwQ 吭哧吭哧改了半天……才过…╮(╯▽╰)╭ longlong的代码很简单我就不写了,下面给出我写的大数的…这个模板说不定以后用的上呢~2333#include <iostream> using namespace std; #include <stdlib.h> #include <string.h> #define MAXN 1000000 int j,l,size,num,x[MAXN]; char ch[MAXN],ans[MAXN]; void sqrt(char *str)//大数求平方 { double i,r,n; size=strlen(str); if (size%2==1) { n=str[0]-48; l=-1; } else { n=(str[0]-48)*10+str[1]-48; l=0; } r=0,num=0; while (true) { i=0; while (i*(i+20*r)<=n) ++i; --i; n-=i*(i+20*r); r=r*10+i; x[num]=(int)i; ++num; l+=2; if (l>=size) break; n=n*100+(double)(str[l]-48)*10+(double)(str[l+1]-48); } } int main() { while (cin>>ch) { int flag=0; sqrt(ch); if((x[num-1]==1)&&num==1)//注意判断条件 { cout<<"1"<<endl; flag=1; goto A; } for(int i=2; i<=5; ++i)//最多计算五次 { for (j=0; j<num; ++j) ans[j]='0'+x[j];//int转char ans[num]=' ';//注意末尾别忘了加结束符 //cout<<ans<<endl; sqrt(ans);//开方 if((x[num-1]==1)&&num==1) { cout<<i<<endl;//输出次数 flag=1;//标记 break; } } A: if(!flag) cout<<"TAT"<<endl;//超过五次或者为0时 } return 0; } (编辑:温州站长网) 【声明】本站内容均来自网络,其相关言论仅代表作者个人观点,不代表本站立场。若无意侵犯到您的权利,请及时与联系站长删除相关内容! |